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Beginning Activity Beginning Activity 1: Exploring a Proposition about Factorials

Definition.

If n is a natural number, we define n factorial, denoted by n! , to be the product of the first n natural numbers. In addition, we define 0! to be equal to 1.

Using this definition, we see that

0!=13!=123=61!=14!=1234=242!=12=25!=12345=120.

In general, we write n!=123(n1)n or n!=n(n1)21. Notice that for any natural number n, n!=n(n1)!.

1.

Compute the values of 2n and n! for each natural number n with 1n7.

Now let P(n) be the open sentence, “n!>2n.

2.

Which of the statements P(1) through P(7) are true?

3.

Based on the evidence so far, does the following proposition appear to be true or false? For each natural number n with n4, n!>2n.

Let k be a natural number with k4. Suppose that we want to prove that if P(k) is true, then P(k+1) is true. (This could be the inductive step in an induction proof.) To do this, we would be assuming that k!>2k and would need to prove that (k+1)!>2k+1. Notice that if we multiply both sides of the inequality k!>2k by (k+1), we obtain

(27)(k+1)k!>(k+1)2k.

4.

In the inequality in (27), explain why (k+1)k!=(k+1)!.

5.

Now look at the right side of the inequality in (27) Since we are assuming that k4, we can conclude that (k+1)>2. Use this to help explain why (k+1)2k>2k+1.