Exercises Exercises
2.
(a)
(b)
3.
(a)
Follow the steps below to show that
(i)
(ii)
(iii)
To show that we have to prove that cannot be strictly less than Suppose to the contrary that Let Use the result of Exercise 2 to arrive at a contradiction.
(b)
Prove that
(c)
Prove or disprove:
(d)
Prove or disprove:
4.
(a)
(b)
Prove that is a metric on Describe in geometric terms how this metric measures the distance between functions and (This metric is called the supremum metric or the uniform metric on )
5.
(a)
Suppose that there is no positive integer such that Explain how we can conclude that is bounded above.
(b)
(c)
6.
In this exercise we prove two statements that are equivalent to the Archimedean property (see Exercise 5). One of the statements is the following theorem:
Theorem 5.5.
(a)
(i)
Show that if the Archimedean property is true, then so is Theorem 5.5.
(ii)
Show that if Theorem 5.5 is true, then so is the Archimedean property. Conclude that Theorem 5.5 is equivalent to the Archimedean property.
(b)
A second statement that is equivalent to the Archimedean property is the following. Prove that Theorem 5.6 is equivalent to the Archimedean property.
Theorem 5.6.
7.
We can use greatest lower bounds to prove the following theorem. This theorem tells us an important fact β that the rational numbers are what is called dense in the set of real numbers. We prove this theorem in this exercise. Let and be real numbers and assume By the Archimedean property of the natural numbers (see Exercises 5 and Exercise 6), there is a positive integer such that Let
Theorem 5.7.
(a)
(b)
Explain why contains an integer such that if with then It may be helpful to use the Well-Ordering Principle that states
Every subset of the integers that is bounded below contains its infimum.
(The Well-Ordering Principle is one of many axioms that are equivalent to the Principle of Mathematical Induction. These principles are taken as axioms and are assumed to be true.)
(c)
Explain why and Use these inequalities, along with to show that Then find a rational number that is strictly between and
8.
9.
We are familiar with solving the quadratic equation to obtain the solutions But do we really know that the number exists? We address that question in this exercise and demonstrate the existence of the number using the greatest lower bound.
(a)
(b)
(i)
(ii)
(c)
Explain how we have demonstrated the existence of
10.
Similar to Exercise 7 we can prove the following theorem.
Theorem 5.8.
(a)
The first step is to demonstrate the existence of an irrational number. We will do that by proving that is irrational. Proceed by contradiction and assume that is a rational number. That is, for some positive integers and such that and have no positive common factors other than 1.
(i)
(ii)
(b)
Let and be distinct real numbers. Show that there exists an integer and a positive integer such that is an irrational number between and
Hint.
Consider the approach in Exercise 7 .
11.
12.
13.
For each of the following, answer true if the statement is always true. If the statement is only sometimes true or never true, answer false and provide a concrete example to illustrate that the statement is false. If a statement is true, explain why. Throughout, let and be bounded subsets of (a subset of is bounded if it is both bounded above and bounded below).
(a)
Any nonempty subset of is bounded.