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Section Open Intervals and \(\R\)

If we think of a homeomorphism as allowing us to stretch or bend a space, it is reasonable to think that we could stretch an open interval of the form \((a,b)\) infinitely in both directions without altering the nature of the open sets. That is, we should expect that \(\R\) with the standard topology is homeomorphic to \((a,b)\) with the subspace topology.

Activity 15.4.

Let \(a\) and \(b\) be real numbers with \(a \lt b\text{.}\) To show that \((\R, d_E)\) is homeomorphic to \((a,b)\text{,}\) we need a continuous bijection from \(\R\) to \((a,b)\) whose inverse is also continuous.

(a)

First we demonstrate that \((0,1)\) and \(\R\) are homeomorphic using the Euclidean metric topology. Let \(f : (0,1) \to \R\) be defined by
\begin{equation*} f(x) = \tan\left(\pi\left(x-\frac{1}{2}\right)\right)\text{.} \end{equation*}
(i)
Explain why \(f\) maps \((0,1)\) to \(\R\text{.}\)
(ii)
Explain why \(f\) is an injection.
(iii)
Explain why \(f\) is a surjection.
(iv)
Explain why \(f\) and \(f^{-1}\) are continuous.
Hint.
Use a result from calculus.

(b)

The result of (a) is that \(\R\) and \((0,1)\) are homeomorphic spaces. To complete the argument that \(\R\) is homeomorphic to \((a,b)\text{,}\) define a function \(g: (0,1) \to (a,b)\) and explain why your \(g\) is a homeomorphism.
It is left to Exercise 4 to show that \(\R\) is also homeomorphic to any interval of the form \((a,\infty)\) or \((-\infty,b)\text{.}\) Later we will determine if \(\R\) is homeomorphic to intervals of the form \([a,b)\text{,}\) \((a,b]\text{,}\) \([a, \infty)\) or \((-\infty, b]\text{.}\)