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Section Quotient Spaces

As we saw in our preview activity, if we have a surjection p from a topological space (X,ฯ„) to a set Y, we were able to define a topology on Y by making the open sets the sets UโŠ†Y such that pโˆ’1(U) is open in X. This is how we will create what is called the quotient topology. Before we can define the quotient topology, we need to know that this construction always makes a topology.

Activity 16.2.

Let (X,ฯ„X) be a topological space, let Y be a set, and let p:Xโ†’Y be a surjection. Let
ฯ„Y={UโŠ†Yโˆฃpโˆ’1(U)โˆˆฯ„X}.

(b)

Let {Uฮฒ} be a collection of sets in ฯ„Y for ฮฒ in some indexing set J.
(ii)
If J is finite, show that โ‹‚ฮฒโˆˆJUฮฒ is in ฯ„Y.
Activity 16.2 allows us to define the quotient topology.

Definition 16.1.

Let (X,ฯ„X) be a topological space, let Y be a set, and let p:Xโ†’Y be a surjection.
  1. The quotient topology on Y is the set
    {UโŠ†Yโˆฃpโˆ’1(U)โˆˆฯ„X}.
  2. Any function p:Xโ†’Y is a quotient map if p is surjective and for UโŠ†Y, U is open in Y if and only if pโˆ’1(U) is open in X.
  3. If p:Xโ†’Y is a quotient map, then the space Y is the quotient space of X determined by p.

Activity 16.3.

(a)

Let X=R with standard topology, let Y={โˆ’1,0,1}, and define p:Xโ†’Y by
p(x)={1 if x>00 if x=0โˆ’1 if x<0.
Find all of the open sets in the quotient topology.

(b)

Let X=R with standard topology, let Y=[0,1), and define p:Xโ†’Y by
p(x)=xโˆ’โŒŠxโŒ‹,
where โŒŠxโŒ‹ is the largest integer less than or equal to x, (For example โŒŠ1.2โŒ‹=1, and so p(1.2)=1.2โˆ’1=0.2. The function defined by โŒŠxโŒ‹ is also called the floor function. Be careful, note that โŒŠโˆ’0.7โŒ‹=โˆ’1.) Determine the sets in the quotient topology.
Figure 16.2. The graph of p(x)=xโˆ’โŒŠxโŒ‹.
Hint.
The graph of p on [โˆ’2,2] is shown in Figure 16.2.
Another perspective of the quotient topology utilizes the fact that any equivalence relation โˆผ on a set X partitions X into a union of disjoint equivalence classes [x]={yโˆˆXโˆฃyโˆผx}. There is a natural surjection q from X to the space of equivalence classes given by q(x)=[x]. We investigate this perspective in the next activity.

Activity 16.4.

Let X={a,b,c,d,e,f} and let ฯ„={โˆ…,{a},{b},{a,b},{a,b,c},{a,b,c,d},X}. Then (X,ฯ„) is a topological space. Let A={a,b,c} and B={d,e,f}. Define a relation โˆผ on X such that xโˆผy if x and y are both in A or both in B. Assume that โˆผ is an equivalence relation. The sets A and B are the equivalence classes for this relation. That is A=[a]=[b]=[c] and B=[d]=[e]=[f]. Let Xโˆ—={A,B}. Then we can define p:Xโ†’Xโˆ— by sending xโˆˆX to the set to which it belongs. That is, p(x)=[x] for xโˆˆX, or
p(a)=A,p(b)=A,p(c)=A,p(d)=B,p(e)=B, and p(f)=B.
Determine the sets in the quotient topology on Xโˆ—.
The partition of X in Activity 16.4 into the disjoint union of sets A and B defines an equivalence relation on X where xโˆผy if x and y are both in the same set A or B. That is, aโˆผbโˆผc and dโˆผeโˆผf. In this context, the sets A and B are equivalence classes โ€” A=[a] and B=[d], where [x] is the equivalence class of x. This leads to a general construction.
If (X,ฯ„) is a topological space and โˆผ is an equivalence relation on X, we can let X/โˆผ be the set of distinct equivalence classes of X under โˆผ. Then p:Xโ†’X/โˆผ defined by p(x)=[x] is a surjection and X/โˆผ has the quotient topology. The space X/โˆผ is called a quotient space. The space X/โˆผ is also called an identification space because the equivalence relation identifies points in the set to be thought of as the same. This allows us to visualize quotient spaces as resulting from gluing or collapsing parts of the space X.
Figure 16.3. A tube as the identification space X/โˆผ.

Example 16.4.

Let I=[0,1] and let X=Iร—I with standard topology. Define a relation โˆผ on X by (x,y)โˆผ(x,y) if 0<y<1 and 0โ‰คxโ‰ค1, (x,0)โˆผ(x,1) if 0โ‰คxโ‰ค1. It is straightforward to show that โˆผ is an equivalence relation. Let us consider what the identification space X/โˆผ looks like. The space Iร—I is the unit square as shown in Figure 16.3. All points in the interior of the square are identified only with themselves. However, the top side and bottom side are identified with each other in the same direction. Think of X as a piece of paper. We roll up the sides of the square to make the top and bottom sides coincide. The result is that X/โˆผ is the cylinder as shown in Figure 16.3.

Activity 16.5.

Quotient spaces can be difficult to describe. This activity presents a few more examples.

(a)

Let X=[0,1] with standard topology and define an equivalence relation โˆผ on X by 0โˆผ1 and xโˆผx for all x not equal to 0 or 1. What does the quotient space X/โˆผ look like?
Figure 16.5. From left to right: the identifications for parts (i), (ii), and (iii)
Hint.
Think about the relation โˆผ as gluing the points 0 and 1 together.

(b)

Describe quotient spaces of X=Iร—I with standard topology given by the following equivalence relations โˆผ. Depictions of the identifications are shown in Figure 16.5. (Here I is the closed interval [0,1].)
(i)
(x,y)โˆผ(x,y) if 0<y<1 and 0โ‰คxโ‰ค1 and (x,0)โˆผ(1โˆ’x,0) when 0โ‰คxโ‰ค1.
(ii)
(x,y)โˆผ(x,y) if 0<x<1 and 0<y<1, (x,0)โˆผ(x,1) for 0<x<1, (0,y)โˆผ(1,y) for 0<y<1, and (0,0)โˆผ(0,1)โˆผ(1,0)โˆผ(1,1). (This space is called a Mรถbius strip.)
(iii)
(x,y)โˆผ(x,y) if 0<x<1 and 0<y<1 and (x,y)โˆผ(u,v) if (x,y) and (u,v) are boundary points.
Many other interesting identification spaces can be made. For example, let X=Iร—I and define โˆผ by (x,y)โˆผ(x,y) if 0<x<1 and 0<y<1, (0,y)โˆผ(1,y) for 0<y<1, (x,0)โˆผ(1โˆ’x,1) for 0<x<1. This identification is illustrated in Figure 16.6. The resulting identification space X/โˆผ is a Klein bottle. A nice illustration of this can be seen at maths.orgโ€‰8โ€‰.
Figure 16.6. Identifications for the Klein Bottle.
plus.maths.org/content/introducing-klein-bottle